Find the sum of the given series up to the 50th term. 5, 8, 11------
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Find the sum of the given series up to the 50th term. 5, 8, 11------
3925
3800
3803
3806
This is an arithmetic progression with first term a = 5 and common difference d = 3. The sum of the first n terms is (n/2) * (2a + (n-1)d). For n = 50, sum = (50/2) * (2*5 + 49*3) = 25 * (10 + 147) = 25 * 157 = 3925.
The series is an arithmetic progression with the first term a equal to 5 and the common difference d equal to 3. Using the sum formula for an arithmetic progression, Sn = n/2 * (2a + (n - 1)d), we substitute the values to get S50 = 50/2 * (2(5) + (50 - 1)3). Solving inside the parentheses gives 10 + 147, which equals 157, and multiplying by 25 yields 3925.