Find the probability of getting 4 at least once in two tosses of a fair dice.
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Find the probability of getting 4 at least once in two tosses of a fair dice.
11/36
3/16
7/36
25/36
Total outcomes = 36. Outcomes with no 4 = 5 * 5 = 25. Outcomes with at least one 4 = 36 - 25 = 11. Probability = 11/36.
The total number of outcomes for two tosses of a fair die is 6 multiplied by 6, or 36. To find the probability of getting 4 at least once, use the complementary event method by calculating the probability of never getting a 4. The probability of not rolling a 4 on both tosses is 5 divided by 6 multiplied by 5 divided by 6, which gives 25 divided by 36. Subtracting this from 1 gives the result: 1 minus 25 divided by 36 equals 11 divided by 36, which is 11/36.