Taking the radius of the circle as R, the chord AB is given by 2R sin(15 degrees) using the half-angle formula for the 30 degree central angle. Since E and F are midpoints of OA and OB, triangle OEF is similar to triangle OAB, making EF exactly half the length of AB, which equals R sin(15 degrees). The length of the minor arc AB is calculated using the arc length formula R theta, yielding R times pi over 6. The ratio of EF to the minor arc is R sin(15 degrees) divided by R pi over 6, and replacing sin(15 degrees) with its exact value of the square root of (2 minus the square root of 3) divided by 2 simplifies the ratio to 3 times the square root of (2 minus the square root of 3) divided by pi.