Find the 9th term in the 1/3, 2/3, 1, 4/3... sequence .
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Find the 9th term in the 1/3, 2/3, 1, 4/3... sequence .
3
5/3
7/3
5/7
The sequence is an arithmetic progression with the first term a = 1/3 and common difference d = 1/3. The nth term is a + (n-1)d. For the 9th term: 1/3 + (9-1)*(1/3) = 1/3 + 8/3 = 9/3 = 3.
The sequence 1/3, 2/3, 1, 4/3 represents an arithmetic progression with the first term a = 1/3 and a common difference d = 1/3. To find the 9th term, use the arithmetic progression formula T_n = a + (n - 1)d. Substitute the values to get T_9 = 1/3 + (9 - 1)(1/3). This simplifies to 1/3 + 8/3, which equals 9/3 or 3.