If two dice are tossed, then what is the probability of getting sum divisible by 6 exactly?
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If two dice are tossed, then what is the probability of getting sum divisible by 6 exactly?
1/3
7/36
1/6
5/36
1/9
There are 36 total outcomes when tossing two dice. Sums divisible by 6 are 6 (outcomes: 1,5; 2,4; 3,3; 4,2; 5,1) and 12 (outcome: 6,6). There are 6 favorable outcomes, so the probability is 6/36 = 1/6.
When two dice are tossed, the sample space has 36 outcomes. The sums divisible by 6 are exactly 6 and 12, occurring in 5 ways and 1 way respectively. Using the addition rule for mutually exclusive events, the total favorable outcomes are 5 plus 1, which equals 6. The probability is 6 divided by 36, which simplifies to 1/6.