Let the common multiplier be x, making the number of red, green, and blue balls 5x, 4x, and 3x, respectively; the total is 12x. The probability of drawing two balls of different colors is found by subtracting the probability of drawing the same colors from one, giving 1 - [ (5C2 + 4C2 + 3C2) / 12C2 ] = 47/70. Solving this equation yields 1 - (10x^2 + 6x^2 + 3x^2) / (72x^2 - 6x) = 47/70, which simplifies to (72x - 19) / 12(12x - 1) = 47/70. Cross-multiplying and simplifying gives 420x - 95 = 564x - 47, resulting in 48 = 144x, so x = 3. The number of blue balls is 3x = 3 * 3 = 9.