What is the eighth term of the sequence 5, 7, 11, 19 _ _ _ _ _?
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256
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67
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131
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259
Sequence: 5, 7, 11, 19. Differences: 2, 4, 8. This is a geometric progression of differences (2^1, 2^2, 2^3). Next differences: 16, 32, 64, 128. Terms: 19+16=35 (5th), 35+32=67 (6th), 67+64=131 (7th), 131+128=259 (8th).
The differences between the consecutive terms of the sequence are formed by powers of 2. The difference between 5 and 7 is 2, the difference between 7 and 11 is 4, and the difference between 11 and 19 is 8. Continuing this pattern, the next differences are 16, 32, 64, and 128, making the fifth term 19 plus 16 which is 35, the sixth term 35 plus 32 which is 67, the seventh term 67 plus 64 which is 131, and the eighth term 131 plus 128 which is 259. Therefore, the eighth term is 259.