What is the area of the circle (approximately) inscribed in a triangle with side lengths 12 cm, 16 cm and 20 cm?
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What is the area of the circle (approximately) inscribed in a triangle with side lengths 12 cm, 16 cm and 20 cm?
48 square cm
50 square cm
52 square cm
54 square cm
The triangle is a right triangle (12^2 + 16^2 = 20^2). The inradius r of a right triangle is (a+b-c)/2 = (12+16-20)/2 = 4. Area of circle = pi * r^2 = 3.14 * 16 = 50.24, which is approximately 50.
The sides 12 cm, 16 cm and 20 cm form a right-angled triangle, so its area is 1/2 * 12 * 16 = 96 sq cm. The semi-perimeter is (12 + 16 + 20) / 2 = 24 cm, making the radius of the inscribed circle 96 / 24 = 4 cm. The area of this inscribed circle is pi * r^2, which is 3.14159 * 16, approximately equal to 50 sq cm. The result is 50 square cm.