Multiple choice

In a bag, there are 15 red balls and 10 green balls. Three balls are selected at random. The probability of selecting 2 red balls and 1 green ball is:

  1. 21 46

  2. 25 117

  3. 3 25

  4. 1 50
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A Correct answer
Explanation

The probability is C(15,2) × C(10,1) divided by C(25,3). This equals 1050/2300 = 21/46.

AI explanation

From a total of 25 balls, the number of ways to choose 3 balls is 25C3, equaling 2300. The favorable ways to choose 2 red balls from 15 and 1 green ball from 10 are 15C2 multiplied by 10C1, yielding 1050. Therefore, the probability is 1050 divided by 2300, which simplifies to 21/46.

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