Multiple choice

Consider the following: AB is a diameter of a circle with centre O. Radius OP is perpendicular to AB. Let Q be any point on arc PB. What is ∠BAP equal to?

  1. 30°

  2. 40°

  3. 45°

  4. 60°

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

AB is diameter, O is center. OP is perpendicular to AB, so angle AOP = 90 degrees. Triangle OAP is an isosceles right triangle (OA=OP=radius). Thus, angle OAP = 45 degrees. Since O, A, B are collinear, angle BAP is the same as angle OAP, which is 45 degrees.