If the perimeter of a right-angled triangle is 30 cm and the hypotenuse is 13 cm, then what is the area of the triangle?
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If the perimeter of a right-angled triangle is 30 cm and the hypotenuse is 13 cm, then what is the area of the triangle?
24 cm2
27 cm2
30 cm2
36 cm2
Perimeter = a+b+c = 30. Hypotenuse c = 13. a+b = 17. a^2+b^2 = 13^2 = 169. (a+b)^2 = a^2+b^2+2ab. 17^2 = 169 + 2ab. 289 = 169 + 2ab. 2ab = 120. Area = 1/2 * ab = 1/2 * 60 = 30.
The sum of the two legs of the triangle equals 30 cm minus 13 cm, which is 17 cm. Let the legs be a and b, so the Pythagorean theorem gives a squared plus b squared equals 13 squared, or 169. Squaring the sum of the legs gives 17 squared equals 289, which equals a squared plus b squared plus 2ab. Substituting 169 for a squared plus b squared gives 289 equals 169 plus 2ab, so 2ab equals 120. The area of the right-angled triangle is one half of ab, which is 30 cm squared.