A man travelled to his hometown at 5 kmph more than his usual speed and reached 2 hours early. On another occasion, he travelled at 2 kmph less than his usual speed and reached the destination 1.5 hours later than usual. What is the usual speed of the man, if distance between the man and his home is 60 km.

Using the formula time equals distance divided by speed, the first journey takes (60 / (x + 5)) hours and the usual time is (60 / x) hours, giving the equation (60 / x) - (60 / (x + 5)) = 2. The second journey gives the equation (60 / (x - 2)) - (60 / x) = 1.5, and solving this system of equations yields the usual speed of 10 kmph.

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