Multiple choice

There are 15 balls numbered from 1 to 15 in a bag. Three balls are drawn from bag without replacement. What is the probability that the all three drawn balls are odd numbered ball?

  1. 1/13

  2. 8/65

  3. 8/15

  4. 7/15

  5. 1/2
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B Correct answer
Explanation

Total balls = 15. Odd balls = {1, 3, 5, 7, 9, 11, 13, 15} (8 balls). Probability = (8/15) * (7/14) * (6/13) = (8/15) * (1/2) * (6/13) = 4/15 * 6/13 = 24/195 = 8/65.

AI explanation

From the numbers 1 to 15, there are 8 odd numbered balls. The probability of drawing an odd ball on the first, second, and third draws without replacement is 8/15, 7/14, and 6/13 respectively. Multiplying these probabilities together gives (8/15) multiplied by (1/2) multiplied by (6/13). The result is 8/65.

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