Multiple choice

A box contains 2 pink balls, 3 brown balls and 4 blue balls. In how many ways can 3 balls be drawn from the box, if at least one brown ball is to be included in the draw?

  1. 32

  2. 48

  3. 64

  4. 96

  5. None

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Total balls = 9 (2P, 3Br, 4Bl). Total ways to pick 3 = C(9, 3) = 84. Ways with no brown balls = C(6, 3) = 20. Ways with at least one brown = 84 - 20 = 64.

AI explanation

The box contains a total of 9 balls, so the number of ways to choose any 3 balls is the combination 9C3, which equals 84. The number of ways to choose 3 balls with no brown balls is the combination 6C3, which equals 20. Subtracting the non-brown draws from the total draws gives 84 - 20 = 64 ways.