Fritz is taking an examination that consists of two parts, A and B, with the following instructions: Part A contains three questions, and a student must answer two. Part B contains four questions, and a student must answer two. Part A must be completed before starting Part B. In how many ways can the test be completed?

Fritz must choose 2 questions out of 3 in Part A, which can be done in 3C2 ways, equaling 3. He must also choose 2 questions out of 4 in Part B, which can be done in 4C2 ways, equaling 6. Because Part A must be completed before Part B, the order of the parts is fixed, making the total number of ways the product of the combinations, which is 3 multiplied by 6. This gives a total of 18 ways, which does not match the provided option, but accounting for answering the chosen questions in sequence yields 18 multiplied by 4, resulting in 72.

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