Multiple choice

Joshua started from city A at 11:30 am and reached city B at 3:50 pm. If he traveled at a speed of 70 mph, what is the distance between city A and city B?

  1. 273.3 miles

  2. 283.3 miles

  3. 293.3 miles

  4. 303.3 miles
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The time elapsed from 11:30 am to 3:50 pm is 4 hours and 20 minutes, which is 4 + 20/60 = 4.333 hours. Distance = speed * time = 70 mph * 4.333 hours = 303.33 miles.

AI explanation

The total time taken from 11:30 am to 3:50 pm is 4 hours 20 minutes, which equals 4 and 1/3 hours or 13/3 hours. Using the formula distance equals speed multiplied by time, the calculation is 70 multiplied by 13/3. This equals 910/3, which is 303.3 miles.

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