Multiple choice

A train covering first third of a 75-mile trip took twice the time as the rest of the trip. If the first third took h hours, what was the average speed, in miles per hour, for the journey?

  1. 25/h

  2. 75/2h

  3. 50/h

  4. 125/2h
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

First third = 25 miles. Let time for first third be h. Remaining 50 miles took h/2. Total time = h + h/2 = 3h/2. Average speed = Total distance / Total time = 75 / (3h/2) = 75 * 2 / 3h = 50/h.

AI explanation

The first third of the 75-mile trip is 25 miles and takes h hours, meaning the rest of the trip is 50 miles. Since this 50-mile section took half the time of the first section, its time is h / 2 hours, making the total time for the journey h + h / 2 equals 3h / 2 hours. Using the average speed formula of Total Distance divided by Total Time, the average speed is 75 / (3h / 2). Simplifying this yields 75 multiplied by 2 / 3h, which equals 50 / h miles per hour.

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