Directions: Answer the question independently. A group of 4 women and 3 men can do a piece of work in 24 days, while a group of 3 women and 4 men can do a piece of work in 25 days. In how many days can a group of 2 women and 4 men can do the same work.

Using the equation method, 4w + 3m = 1/24 and 3w + 4m = 1/25. Multiplying the first equation by 4 and the second by 3 gives 16w + 12m = 1/6 and 9w + 12m = 3/75. Subtracting the second from the first yields 7w = 1/6 - 3/75 = 19/150, meaning w = 19/1050. By substituting back, m equals 1/25 - 3w = 1/25 - 19/350 = 6/175. For 2 women and 4 men, the daily work is 2 multiplied by 19/1050 plus 4 multiplied by 6/175, equaling 1/30 of the task per day, so the work is completed in 30 days.

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