Multiple choice

In how many different ways can six players be arranged in a line such that two of them, Ajeet and Mukherjee are never together?

  1. 120

  2. 240

  3. 360

  4. 480

  5. 670
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Total arrangements of 6 players = 6! = 720. Arrangements where Ajeet and Mukherjee are together: treat them as one unit, so 5! * 2! = 120 * 2 = 240. Arrangements where they are not together = 720 - 240 = 480.

AI explanation

The total number of ways to arrange six players in a line is given by 6! = 720. To find the arrangements where Ajeet and Mukherjee are together, treat them as a single unit, which gives 5! arrangements for the unit, multiplied by 2! for their internal arrangement, resulting in 120 * 2 = 240. Subtracting the together arrangements from the total gives 720 - 240 = 480.

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