What would be the 19th term of the given sequence? 1, 5, 9, 13, …
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What would be the 19th term of the given sequence? 1, 5, 9, 13, …
92
84
75
73
The sequence is an arithmetic progression with a first term a = 1 and a common difference d = 4. The formula for the n-th term is a + (n-1)d. For the 19th term, this is 1 + (19-1)*4 = 1 + 18*4 = 1 + 72 = 73.
The series follows the pattern of an arithmetic progression with a first term of 1 and a common difference of 4. The nth term of an arithmetic progression is found using the formula a + (n - 1)d. Applying this to find the 19th term gives 1 + (19 - 1) * 4, which simplifies to 1 + 72 = 73. The result is 73.