Multiple choice

A person gives a contract of repairing of his home to two workers A and B with a contract amount of Rs. 13500. If worker A is 3 times more efficient than worker B and they both can complete the work in 45 days, what is the amount paid to worker A for 10 days?

  1. Rs. 2000

  2. Rs. 2500

  3. Rs. 2750

  4. Rs. 2250
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

A is 3 times as efficient as B. A = 3B. Combined efficiency (A+B) = 4B. They finish in 45 days, so total work = 4B * 45 = 180B. Amount for A = (Efficiency of A / Total Efficiency) * Total Amount = (3B / 4B) * 13500 = 0.75 * 13500 = 10125 for 45 days. Amount for 10 days = (10125 / 45) * 10 = 225 * 10 = 2250.

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