Find the number of terms of the given series. 6, 18, 30 ... 198
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Find the number of terms of the given series. 6, 18, 30 ... 198
6
8
10
17
14
This is an arithmetic progression with a=6, d=12, l=198. Formula: l = a + (n-1)d. 198 = 6 + (n-1)12. 192 = (n-1)12. 16 = n-1. n = 17.
Using the arithmetic progression formula for the nth term, where the first term a is 6, the common difference d is 12, and the last term is 198, calculate the total number of terms. Apply the formula Tn = a + (n - 1)d by substituting the values to get 198 = 6 + (n - 1)12. Solving this equation gives 192 = 12(n - 1), so n - 1 equals 16 and n equals 17.