Multiple choice

If the radius of the circle is 15 cm and length of the one of the cords is 24 cm, find the distance of midpoint of the chord from the centre of the circle.

  1. 9 cm

  2. 12 cm

  3. 15 cm

  4. 18 cm

  5. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

A perpendicular from the center to a chord bisects the chord. This forms a right triangle with the radius (15) as the hypotenuse and half the chord (12) as one leg. The distance from the center is the other leg: sqrt(15^2 - 12^2) = sqrt(225 - 144) = sqrt(81) = 9 cm.

AI explanation

Using the perpendicular distance formula from the center to a chord, d = √(r² - (L/2)²), we substitute r = 15 and L = 24. This gives d = √(225 - 144), which equals √81. The distance is 9 cm.

Keep practicing — related questions