A boy takes 3 hours more when he decreases his speed by 40 miles per hour. If the total distance is 240 miles, what was his actual speed?
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A boy takes 3 hours more when he decreases his speed by 40 miles per hour. If the total distance is 240 miles, what was his actual speed?
80 miles per hour
90 miles per hour
120 miles per hour
125 miles per hour
130 miles per hour
Let speed be v. Time taken at speed v is 240/v. Time taken at speed (v-40) is 240/(v-40). The difference is 240/(v-40) - 240/v = 3. Solving this quadratic equation: 240v - 240(v-40) = 3v(v-40) leads to 9600 = 3v^2 - 120v, or v^2 - 40v - 3200 = 0. Factoring gives (v-80)(v+40) = 0, so v = 80.
Let the actual speed be v miles per hour, so the decreased speed is v - 40 miles per hour. Using the given difference in time, we write the equation 240 / (v - 40) - 240 / v = 3. Solving 240v - 240(v - 40) = 3v(v - 40) yields 9600 = 3v squared - 120v, which simplifies to v squared - 40v - 3200 = 0. Factoring gives (v - 80)(v + 40) = 0, and discarding the negative root leaves the actual speed at 80 miles per hour.