What is the probability of getting a total of 15 when three dice are tossed?
-
3/216
-
10/216
-
12/216
-
15/216
-
1/6
Total outcomes = 6^3 = 216. Sum of 15: (6,6,3)x3, (6,5,4)x6, (5,5,5)x1. Total = 3+6+1 = 10. Probability = 10/216.
When three dice are tossed, the total number of outcomes in the sample space is 6 cubed, which equals 216. To get a sum of 15, the favorable outcomes are the permutations of (4, 5, 6), (3, 6, 6), (5, 5, 5), and (4, 5, 6). Counting these gives 6 permutations for (4, 5, 6), 3 permutations for (3, 6, 6), 1 for (5, 5, 5), and no others fit, but recounting shows the valid combinations are (4, 5, 6) yielding 6 ways, (5, 5, 5) yielding 1 way, and (3, 6, 6) yielding 3 ways, totaling 10 favorable outcomes. The probability is therefore 10 divided by 216.