Multiple choice

A car moving with a speed of 12 m/s is subjected to brakes which produces a deceleration of 6 m/s2. The car takes 2s to stop after the application of brakes. What is the distance covered by the car after the application of brakes?

  1. 12 m

  2. 24 m

  3. 36 m

  4. 48 m
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A Correct answer
Explanation

Using v^2 = u^2 + 2as. Final velocity v = 0, initial u = 12, acceleration a = -6. 0 = 144 + 2(-6)s => 12s = 144 => s = 12.

AI explanation

Using the equation of motion, S = ut + (1/2)at^2, where the initial velocity u is 12 m/s, acceleration a is -6 m/s^2, and time t is 2 seconds. The distance equals (12 * 2) + (0.5 * -6 * 4), which simplifies to 24 - 12. The distance covered by the car is 12 m.

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