Multiple choice

What is the 9th term of the sequence 2, 8, 18, 32,...?

  1. 162

  2. 163

  3. 164

  4. 166
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A Correct answer
Explanation

The sequence is 2, 8, 18, 32... which can be written as 2(1^2), 2(2^2), 2(3^2), 2(4^2)... The n-th term is 2(n^2). For n=9, the term is 2(9^2) = 2(81) = 162.

AI explanation

Each term in this sequence is double the square of its position, giving the general formula 2n^2. Applying this formula for the 9th term, we calculate 2 times 9 squared. This results in 2(81), which equals 162.

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