Find the nth term of the given sequence. 9, 16, 25, 36, 49, …
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Find the nth term of the given sequence. 9, 16, 25, 36, 49, …
2n2 - 1 + 4n
n2 + 4n + 4
n2 - 3n + 2
n2 + 1 + 2n
The sequence is 9, 16, 25, 36, 49, which are squares of 3, 4, 5, 6, 7. This is (n+2)^2 = n^2 + 4n + 4.
The sequence consists of perfect squares starting from 3 squared, meaning the nth term can be expressed as (n + 2) squared. Expanding this algebraic identity yields n squared plus 4n plus 4. You can verify this by checking the first term: 1 squared plus 4 times 1 plus 4 equals 9.