What is the sum of the 51st and 15th term of the given sequence? 2, 7, 12, ...
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What is the sum of the 51st and 15th term of the given sequence? 2, 7, 12, ...
316
320
324
328
The sequence is arithmetic with a=2 and d=5. The n-th term is a + (n-1)d. 51st term = 2 + 50*5 = 252. 15th term = 2 + 14*5 = 72. Sum = 252 + 72 = 324.
The sequence is an arithmetic progression with the first term a = 2 and a common difference d = 5, so we use the nth term formula: a + (n - 1)d. The 51st term is 2 + 50 times 5, which equals 252, and the 15th term is 2 + 14 times 5, which equals 72. Adding these two terms together, 252 + 72, gives the sum of 324.