Three persons A, B and C together can do a piece of work in 36 days. A and B together can do five times as much work as C alone; B and C together can do as much work as A alone. If A and C together can do n times as much work as B alone, then what is the value of n?

Since A and B do five times as much work as C, the ratio of their combined work to C's work is 5:1, making A+B+C equal to 6 units of C's work. Because B+C equals A, substituting this into A+B+C = 36 gives 2A = 36, so A alone takes 72 days. Using the relation B+C = A with the total sum reveals A+C is twice as much work as B, making the value of n equal to 2.

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