Multiple choice

Jaya walks from her house at 5 kmph and reaches her school 10 minutes late. If her speed had been 6 kmph she would have reached 15 minutes early. The distance between her school and her house is

  1. 8 km

  2. 12.5 km

  3. 10

  4. 12
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let distance be d. Time at 5 kmph = d/5. Time at 6 kmph = d/6. Difference in time = 10 min late + 15 min early = 25 min = 25/60 hours. d/5 - d/6 = 25/60. d/30 = 25/60. d = 12.5 km.

AI explanation

Let the required distance be D km and the correct time to reach the school be T hours. Using the time equals distance divided by speed formula, we get two equations: D/5 = T + 10/60 and D/6 = T - 15/60. Subtracting the second equation from the first gives D/5 - D/6 = 25/60, which simplifies to D/30 = 5/12, resulting in a distance of 12.5 km.

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