Multiple choice

Moving at (4/5) of his usual speed, Andy is 16 minutes late to his destination. Find the usual time taken by him to cover that distance to reach his destination?

  1. 80 mins

  2. 48 mins

  3. 64 mins

  4. 32 mins
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let the usual speed be v and usual time be t. Then distance d = vt. New speed is (4/5)v, so new time is d / (4/5)v = (5/4)t. The difference in time is (5/4)t - t = (1/4)t = 16 minutes. Thus, t = 64 minutes.

AI explanation

When the new speed becomes 4/5 of the usual speed, the new time required becomes 5/4 of the usual time. The increase in time is 1/4 of the usual time, which equals the 16 minutes delay. By equating 1/4 of the usual time to 16 minutes, the usual time is calculated as 64 minutes.

Keep practicing — related questions