A can finish a piece of work in a certain number of days. B takes 45% more number of days to finish the same work independently. They worked together for 58 days and then the remaining work was done by B alone in 29 days. In how many days could A have completed the work, had he worked alone?

Let A's time be x days. Since B takes 45% more days, B's time is 1.45x, which makes their efficiency ratio B to A equal to 1 to 1.45, or 20 to 29. Let their efficiencies be 20 and 29 units respectively. The equation for the work done is (58 * (20 + 29)) + (29 * 20) = Total Work, which simplifies to 2842 + 580 = 3422 units. Equating A's total capacity, 29 * x = 3422, we find x = 118 days.

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