Multiple choice

A motorbike leaves point A at 1 pm and moves towards point B at a uniform speed. A car leaves point B at 2 pm and moves towards point A at a uniform speed which is double that of the motorbike. They meet at 3:40 pm at a point which is 168 km away from A. What is the distance, in km, between A and B?

  1. 364

  2. 378

  3. 380

  4. 388
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Motorbike travels from 1 pm to 3:40 pm (2 hours 40 mins = 8/3 hours). Distance = 168 km. Speed_m = 168 / (8/3) = 63 km/h. Car travels from 2 pm to 3:40 pm (1 hour 40 mins = 5/3 hours). Speed_c = 2 * 63 = 126 km/h. Distance_c = 126 * (5/3) = 210 km. Total distance = 168 + 210 = 378 km.

AI explanation

The motorbike travels for 2 hours and 40 minutes, or 8/3 hours, before the meeting, so its speed is 168 divided by 8/3, which equals 63 km per hour. The car travels for 1 hour and 40 minutes, or 5/3 hours, at double this speed, which is 126 km per hour. The car covers a distance of 126 multiplied by 5/3, giving 210 km. Adding the distance covered by the motorbike to the distance covered by the car gives a total distance of 168 plus 210, which is 378 km.

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