What is the number of ways of choosing 4 cards from a deck of 52, where all the cards are of the same suit and secondly, where all the cards are of different suits?

For four cards of the same suit, we choose one of the 4 suits and then 4 cards from its 13 cards, calculated as 4C1 x 13C4 = 4 x 715 = 2860. For four cards of different suits, we choose one card from each of the four suits, calculated as 13C1 x 13C1 x 13C1 x 13C1 = 13 x 13 x 13 x 13 = 28561.

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