Multiple choice

Three runners A, B and C are running around a circular track. The ratio of their speeds is 3 : 4 : 5. They meet exactly 12th time at the end of an hour at the starting point. A covers 4920 m less distance than C in 1 hour. What is the distance travelled by B in 1 hour?

  1. 9920 m

  2. 9840 m

  3. 9960 m

  4. 9460 m

  5. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Ratio of speeds = 3:4:5. Let speeds be 3k, 4k, 5k. In 1 hour, distances are 3k, 4k, 5k. 5k - 3k = 4920 => 2k = 4920 => k = 2460. Distance of B = 4k = 4 * 2460 = 9840 m.

AI explanation

Using the speed ratio of 3 : 4 : 5 and the difference of 4920 m between the distances covered by C and A, we can calculate the speed of B. The distance difference corresponds to 2 units in the ratio, meaning 1 unit equals 2460 m. Since B's speed represents 4 units, the distance B travels in 1 hour is 4 multiplied by 2460 m, which equals 9840 m.

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