Multiple choice

The distance between two stations A and B is 138 km. A train starts from A towards B and another from B to A at the same time and they meet after 6 hours. The train travelling from A to B is slower by 7 kmph compared to other train from B to A, then find the speed of the slower train?

  1. 8

  2. 9

  3. 10

  4. 11
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A Correct answer
Explanation

Let speeds be v and v+7. Relative speed = 2v+7. Distance = 138, time = 6. 6(2v+7) = 138. 2v+7 = 23. 2v = 16, v = 8.

AI explanation

Using the relative speed concept for two objects moving in opposite directions, the sum of their speeds equals the total distance divided by the time to meet. Therefore, the sum of their speeds is 138 km / 6 hours = 23 kmph. Given that the difference in their speeds is 7 kmph, we solve the system of equations x + y = 23 and x - y = 7. Adding both equations gives 2x = 30, so the faster train travels at 15 kmph and the slower train travels at 8 kmph. The speed of the slower train is 8.

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