A thief escapes at 2 pm. A policeman starts chasing him from 5 pm at a speed of 7 km per hour. At what time will the policeman catch-up with the thief if the thief runs at 5.5 km per hour?

By 5 pm, the thief has run for 3 hours at 5.5 km per hour, giving him a head start of 16.5 km. The policeman's relative speed is 7 km per hour minus 5.5 km per hour, which equals 1.5 km per hour. Using the formula Time equals Distance divided by Speed, the time taken to catch the thief is 16.5 km divided by 1.5 km per hour, resulting in 11 hours. Adding 11 hours to the policeman's start time of 5 pm brings the catch-up time to 4 am.

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