N number of men can finish a piece of work in 40 days. If there were 8 more men, the work could be finished in 10 days less. What will be double the original no of men?

Using the constant work formula M1 times D1 equals M2 times D2, the initial work is N times 40, and the second scenario is (N plus 8) times 30. Setting them equal gives 40N equals 30N plus 240, which simplifies to 10N equals 240, resulting in an original number of 24 men. Doubling this original amount gives 48 men.

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