Three men can do a piece of work in six days. 4 women can finish the same piece of work in nine days, whereas 9 children can complete the same work in five days. 2 men, 6 women and 10 children work for 1 day. If the remaining work has to be completed the next day only by men, then how many men would be required to complete the work?

Assume the least common multiple of the days is the total work, so total work is 90 units. The daily work of one man is 5 units, one woman is 2.5 units, and one child is 2 units. The work done by 2 men, 6 women, and 10 children in one day is (10 + 15 + 20) = 45 units, leaving 45 units of remaining work. To finish the 45 remaining units in one day, the number of men required is 45 / 5, which is 9 men.

• Thanks
• Wrong explanation