Multiple choice

A bag contains one rupee, 50 paise, 25 paise and 10 paise coins in the proportion 1 : 3 : 5 : 7. If the total amount is Rs. 22.25, find the number of coins of each kind.

  1. Rs. 1, 5; 50 paise 25; 25 paise, 15; 10 paise, 25

  2. Rs. 1, 5; 50 paise 15; 25 paise, 25; 10 paise, 35

  3. Rs. 1, 5; 50 paise 25; 25 paise, 15; 10 paise, 35

  4. Rs. 1, 5; 50 paise 25; 25 paise, 25; 10 paise, 25
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the number of coins be 1x, 3x, 5x, 7x. The value is 1(x) + 0.5(3x) + 0.25(5x) + 0.1(7x) = 22.25. This gives x + 1.5x + 1.25x + 0.7x = 4.45x = 22.25. Solving for x gives x = 5. The number of coins are 5, 15, 25, 35.

AI explanation

Using the given proportion of 1 to 3 to 5 to 7, let the number of Re. 1, 50 paise, 25 paise, and 10 paise coins be x, 3x, 5x, and 7x, respectively. The total value in rupees is represented by the equation 1x plus 0.50 times 3x plus 0.25 times 5x plus 0.10 times 7x equaling 22.25. Simplifying this gives x plus 1.5x plus 1.25x plus 0.7x, which results in 4.45x equaling 22.25. Solving for x gives 5, meaning there are 5 Re. 1 coins, 15 50 paise coins, 25 25 paise coins, and 35 10 paise coins.

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