Multiple choice

Anmol had 10 paise, 25 paise and 50 paise coins in the ratio of 10 : 8 : 9 respectively. After giving Rs. 20 his mother he has Rs. 40. How many 50 paise coins did he have?

  1. 72

  2. 60

  3. 54

  4. 35
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let the number of coins be 10x, 8x, 9x. Total value = 0.10(10x) + 0.25(8x) + 0.50(9x) = 1x + 2x + 4.5x = 7.5x. After giving 20, he has 40, so total was 60. 7.5x = 60 => x = 8. Number of 50 paise coins = 9x = 9 * 8 = 72.

AI explanation

Before giving Rs. 20 to his mother, Anmol had a total of Rs. 60. Let the common multiplier for the coin ratio be x, meaning he had 10x, 8x, and 9x coins of 10 paise, 25 paise, and 50 paise respectively. The total value in rupees is calculated as (10x multiplied by 10 + 8x multiplied by 25 + 9x multiplied by 50) divided by 100, which simplifies to (100x + 200x + 450x) divided by 100, equaling 7.5x. Setting this equal to Rs. 60 gives x = 8. The number of 50 paise coins is 9x, which is 9 multiplied by 8, resulting in 72 coins.

Keep practicing — related questions