Multiple choice

Ramesh divides 2 plots among his five daughters Meena, Sita, Rekha, Geeta, and Rani. The first plot is divided in the ratio 3 : 2 : 4 : 1 : 5, and the second plot in the ratio 2 : 3 : 1 : 5 : 4. If the second plot is three times the size of the first, then which daughter receives the largest share of plot?

  1. Meena

  2. Sita

  3. Rani

  4. Geeta
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let plot 1 size = P, plot 2 size = 3P. Total shares in plot 1 = 3+2+4+1+5 = 15. Total shares in plot 2 = 2+3+1+5+4 = 15. Rani's share = (5/15)P + (4/15)3P = (5/15)P + (12/15)P = 17/15P. Comparing others: Meena = 3/15P + 6/15P = 9/15P. Sita = 2/15P + 9/15P = 11/15P. Rekha = 4/15P + 3/15P = 7/15P. Geeta = 1/15P + 15/15P = 16/15P. Rani has the largest.

AI explanation

Let the value of one part of the first plot be x and one part of the second plot be y; the sums of the ratios are 15 and 15, so 15y = 3 * 15x, meaning y = 3x. The shares for Geeta are x + 5y = x + 15x = 16x, and the shares for Rani are 5x + 4y = 5x + 12x = 17x. Since 17x is greater than 16x and all other daughters' combined shares are smaller, Rani receives the largest share.

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