The ages of four brothers are consecutive composite numbers. The age of the eldest brother's age is a multiple of 19 and less than 100. Eight years ago, the second youngest brother's age was 3^y, where y is a positive integer. Find the age (in years) of the youngest brother after five years.

Consecutive composite numbers: 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24, 25, 26, 27, 28, 30, 32, 33, 34, 35, 36, 38, 39, 40, 42, 44, 45, 46, 48, 49, 50, 51, 52, 54, 55, 56, 57, 58, 60, 62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77, 78, 80, 81, 82, 84, 85, 86, 87, 88, 90, 91, 92, 93, 94, 95, 96, 98, 99. Eldest is multiple of 19: 19, 38, 57, 76, 95. If eldest is 76, brothers are 76, 75, 74, 73 (not composite). If 77, 76, 75, 74 (all composite). 8 years ago, 2nd youngest (75) was 67 (not 3^y). If eldest is 39, brothers 39, 38, 36, 35. 8 years ago, 2nd youngest (36) was 28 (not 3^y). Checking 34, 35, 36, 38. 8 years ago, 35-8=27=3^3. Youngest is 34. After 5 years, 34+5=39.