Multiple choice

Ratio of present age of A, B, C and D is 6 : 8 : 11 : 15 . Sum of their ages 4 years before was 64years then what is the difference of present age of B and D.

  1. 8 years

  2. 14 years

  3. 4 years

  4. 22 years

  5. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the ages be 6x, 8x, 11x, and 15x. Four years ago, the sum was (6x-4) + (8x-4) + (11x-4) + (15x-4) = 40x - 16 = 64, which gives 40x = 80, so x = 2. The present ages are 12, 16, 22, and 30; the difference between B (16) and D (30) is 14.

AI explanation

Let the present ages of A, B, C, and D be 6x, 8x, 11x, and 15x respectively based on the ratio. Four years ago, their ages were 6x - 4, 8x - 4, 11x - 4, and 15x - 4. The sum of these past ages is 40x - 16, which equals 64, so 40x equals 80 and x equals 2. The difference between the present ages of B and D is 15x minus 8x, which is 7x. Substituting x equals 2 gives a difference of 14 years.

Keep practicing — related questions