Multiple choice

A father is twice as old as his son. Five years ago, the sum of their ages was 45. What is the father's present age is approximately?

  1. 37

  2. 31

  3. 40

  4. 45

  5. 50
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A Correct answer
Explanation

Let son's age be x, father's be 2x. Five years ago: (x-5) + (2x-5) = 45. 3x - 10 = 45, 3x = 55, x = 18.33. Father's age = 2x = 36.66, which is approximately 37.

AI explanation

Let the present ages of the father and son be F and S respectively. Since the father is twice as old as his son, F = 2S. Five years ago, the sum of their ages was (F - 5) + (S - 5) = 45, which simplifies to F + S = 55. Substituting F = 2S into the sum gives 3S = 55, so S equals 18.33 and the father's age F is 2 * 18.33, which is approximately 37.

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