Multiple choice

Q.59.A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present age of the mother? A.38 years B.40 years C.43 years D.45 years E. None

  1. A

  2. B

  3. C

  4. D

  5. E
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let the son's present age be x, so the mother's age is 2x. Twenty years ago, 2x - 20 = 10(x - 20), which gives x = 22.5. The mother's present age is therefore 45 years, corresponding to option D.

AI explanation

Let the son's present age be x and the mother's present age be 2x. Twenty years ago, their ages were (x - 20) and (2x - 20), leading to the equation 2x - 20 = 10(x - 20). Solving 2x - 20 = 10x - 200 gives 8x = 180 and x = 22.5, which means the mother is 2(22.5) = 45 years old. The present age of the mother is 45 years.

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