Multiple choice

The ages of two persons differ by 16 years. If 6 years ago, the elder one be three times as old as the younger one, find their present ages ?

  1. 12 years

  2. 14 years

  3. 15 years

  4. 16 years

  5. None
Reveal answer Fill a bubble to check yourself
B Correct answer
AI explanation

Let the younger person's present age be y, making the elder person's age y plus 16. Six years ago, the elder was three times the younger, giving the equation y plus 10 equals 3 times y minus 6. Solving y plus 10 equals 3y minus 18 results in 2y equals 28, which means the younger person is 14 years old.

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