Five year hence, average age of A, B and C is 27. Six years ago ratio of age of A and B is 6: 7. B is 8 years younger than C. then, find the difference between C's age and A's age ?

Five years hence, the sum of the ages of A, B, and C is 27 * 3 = 81, making their present sum 81 - 15 = 66. Six years ago, the ratio of A to B was 6:7, so their present ages can be written as 6x + 6 and 7x + 6. Since B is 8 years younger than C, C's present age is 7x + 14, and setting the sum to 66 gives 6x + 6 + 7x + 6 + 7x + 14 = 66, which means 20x = 40 and x = 2. Therefore, the present ages of A and C are 18 and 28, making the difference 10 years.

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