Multiple choice

Had Aparup been 12 years younger, his present age would have been sum of his one son's and one daughter's age. Had Aparup been 2 years elder, his present age would have been 26 years more than his son's present age. If Aparup's present age is four times of his daughter's present age, what will be his son's age 2 years hence? (in years)

  1. 28

  2. 26

  3. 18

  4. 14

  5. 22
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let A, S, D be current ages. (A-12) = S+D. (A+2) = S+26 => A = S+24. A = 4D => D = A/4. Substitute D and S=A-24 into first eq: A-12 = (A-24) + A/4. A-12 = 1.25A - 24 => 12 = 0.25A => A = 48. Then S = 48-24 = 24. Son's age 2 years hence = 24+2 = 26.

AI explanation

Let Aparup's, his son's, and his daughter's present ages be A, S, and D. From the first condition, A - 12 = S + D; from the second, A + 2 = S + 26, which simplifies to A - S = 24; and from the third, A = 4D. Substituting S = A - 24 into the first equation yields A - 12 = A - 24 + D, meaning D = 12. Since A = 4 times 12 = 48, the son's present age is 48 - 24 = 24, and his age 2 years hence will be 24 + 2 = 26 years.

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